If 21 , a , b and -3 are in AP then find the value of (a+b)
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If 21 , a , b and -3 are in AP
we know
a2-a1 = a3- a2 = a4-a3 = d = common difference
a - 21 = b - a = -3 - b
from here we get
a - 21 = -3 -b
a+ b = 21-3
a + b = 18
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Answer:
As the sequence is in AP hence,
As the sequence is in AP hence,a-21=b-a=-3-b
which can be also written as
a-21= -3-b
a+b= 21-3
a+b=18
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