Math, asked by harjotnamsot2005, 9 months ago

if 21 y 5 is a multiple of 9, where y is a digit, what is the value of y?
Rahul and Haroon are in the ratio 5.7. Four years later​

Answers

Answered by Yashipandey99
3

Answer:

For any number to be divisible by 9, the sum of the digits must be 9.

For any number to be divisible by 9, the sum of the digits must be 9.Here if 21y5 is a multiply of nine then

For any number to be divisible by 9, the sum of the digits must be 9.Here if 21y5 is a multiply of nine then2+1+y+5 = 9, or

For any number to be divisible by 9, the sum of the digits must be 9.Here if 21y5 is a multiply of nine then2+1+y+5 = 9, ory = 9–2–1–5 = 1

For any number to be divisible by 9, the sum of the digits must be 9.Here if 21y5 is a multiply of nine then2+1+y+5 = 9, ory = 9–2–1–5 = 1So the number is 2115 and y = 1.

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