IF 215A1 ia a five digit number, divisible by 9, find the value of A.
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Answered by
0
Answer:
0
Step-by-step explanation:
Divisibility rule of 9= the sum should be divisible by 9
So
2+1+5+A+1= no. divisible by 9
9+A= no. divisible by 9
9+0= 9
9+1= 10
9+2= 11
By this we can say that the value of A can be 0.
Hope it helped
Answered by
2
Divisibility rule of 9
If the sum of digits of a number is divisible by 9 then the number is also divisible by 9.
Sum of digits= 2+1+5+A+1=9+A
Therefore, Possible values of A are 0 and 9.
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