Math, asked by nishant813685, 3 months ago

If 2160=2a×3b×5c . Find a,b and c, Hence calculate the value of 3a×2-b×5-c​

Answers

Answered by 05Bhandari
5

Answer:

2

Step-by-step explanation:

to get the value of a,b and c we have to first prime factorise 2160

2160=2×2×2×2×3×3×3×5

which can be written as

2160=2×8 ×3×9 ×5×1

On comparing this with

2160=2a×3b×5c

we get,

a=8

b=9

c=1

Now to find the value of

3a×2-b×5-c

put the values of a, b and c

3(8)×2-(9)×5-1

=48-45-1

=48-46

=2

HOPE THIS WILL HELP YOU

जय महाकाल

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