Math, asked by tagnyad2508, 3 months ago

If 2¹⁹⁹⁸-2¹⁹⁹⁷-2¹⁹⁹⁶+2¹⁹⁹⁵=K. 2¹⁹⁹⁵, Then the value of K is​


Anonymous: 2^1998 - 2^1997 - 2^1996 + 2^1995 = k * 2^1995
2^1995 (2^3 - 2^2 + 2) = k * 2^1995
(2^3 - 2^2 + 2 + 1) = k
8 - 4 - 2 + 1 = k
k = 8 - 5
k = 3
Anonymous: here is your answer :D

Answers

Answered by lulu8540
4

Answer:

3

Step-by-step explanation:

2^(x+y) = 2^x. 2^y

Same separate all powers

1998 = 1995 + 3

1997 = 1995 + 2

1996 = 1995 + 1

1995 = 1995 + 0

Take 2 ^1995 common n cancel on either side

So finally we have

2^3 - 2^2 - 2 + 1= k

K = 3

Answered by Anonymous
1

Answer:

2^1998 - 2^1997 - 2^1996 + 2^1995 = k * 2^1995

2^1995 (2^3 - 2^2 + 2) = k * 2^1995

(2^3 - 2^2 + 2 + 1) = k

8 - 4 - 2 + 1 = k

k = 8 - 5

k = 3

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