Question

If 21a + 21b +21c =714 find the average speed of a,b,c in m/sec

Answer 1

hiiii friend
here is your answer
21a +21b +21c=714
21 (a+b+c)=714
a+b+c=34
so average speed is:⬇⬇⬇
$= \frac{a + b + c}{3} \\ \ = \frac{34}{3} \\ = 11.333$
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