Question

If 21x+ 47y=110 and 47x+21y=162 , find the value X + y and x - y.​

Answer 1

Answer:

The image shows the flow diagram for the breakdown of glucose in yeast.Under which condition these types of products are obtained?* Glucose Pyruvate + Energy In yeast Ethanol + CO2 + Energy (a) in the presence of oxygen O (b) in the absence of oxygen O (c) the presence of carbon dioxide (d) in the absence of carbon dioxide

Answer 2

Step-by-step explanation:

21x+47y=110

47x+21y=162

Multiplying equation (1) by 21, we get

441x+987y=2310

Also multiplying equation (2) by 47, we get

2209x+987y=7614

Now, subtracting equation (3) from (4), we have

(2209x+987y)−(441x+987y)=7614−2310

1768x=5304

⇒x=

1768

5304

=3

Substituting the value of x in equation (1), we have

21×3+47y=110

⇒47y=110−63

⇒y=

47

47

=1

Therefore,

x=3 and y=1.