If 21y8 is a multiple of 6, then find the value of y?
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Answer:
Thus the value of y can be 1, 4, 7.
Step-by-step explanation:
For the number 21y8 to be a multiple of 6, it must be divisible by 6,
As per the rule fora number to be divisible 6, it should be divisible by 2 and 3 both.
The above number is divisible by 2 because in unit's place we have 8 which is divisible by 2.
Next for the number to be divisible by 3, the sum of all the numbers should be divisible by 3.
=>2+1+y+8=11+y should be divisible
by 3
=> y can be only 1 ,4,7
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