Question

If 21y8 is a multiple of 6 where y is a digit then the value og y is

Answer 1

Answer:

Step-by-step explanation:

For the number 21y8 to be a multiple of 6, it must be divisible by 6,

As per the rule fora number to be divisible 6, it should be divisible by 2 and 3 both.

The above number is divisible by 2 because in unit's place we have 8 which is divisible by 2.

Next for the number to be divisible by 3, the sum of all the numbers should be divisible by 3.

=> 2 + 1 + y + 8 = 11 + y should be divisible by 3

=> y can be only 1, 4, 7.

Thus the value of y can be 1, 4, 7.

Answer 2

Answer:

y = 1

Step-by-step explanation:

hint : a number devisible by 2 & 3 will also be devisible by 6.