Question

If 21y8 is a multiple of 6 where y is a digit then the value og y is

Answer 1

Answer:

The values of y can be ⇒ 1 , 4 or 7

Step-by-step explanation:

The divisibility test of 6 says  that a number is divisible by 6 if the number is divisible by both 2 & 3.

The number 21y8 is divisible by 2 (∵ the unit digit is an even number)

To make the number divisible by 3 we have to assign the value of ‘y’ such that the sum of the digits of 21y8 is a multiple of 3.

∴ The values of y can be (I)1 ( 2 + 1 + 1 + 8 = 12 )

(II) 4 ( 2 + 1 + 4 + 8 = 15 )

(III) 7 ( 2 + 1 + 7 + 8 = 18 )

HOPE IT HELPS YOU :)