Question

if 22.5L of nitrogen at 748 mm Hg are compressed to 725 mm Hg at constant temperature. what is the volume?​

Answer 1

P1V1=P2V2

P1=748mmHg

V1=22.5L

P2=725mmHg

V2=P1V1/P2

=748⋅22.5/725

=23.2L

23.2 L

Answer 2

Answer:

After compression, the volume of the gas, V₂, measured is $23.2L$.

Explanation:

Data given,

The volume of nitrogen, V₁ = $22.5L$

The pressure of the gas ( nitrogen ), P₁ = $748mmHg$

After compression, the pressure of the gas ( nitrogen ), P₂ = $725mmHg$

After compression, the volume of the gas, V₂ =

Now, as we know, according to Boyle's law:

• PV = constant  ( at constant temperature )

Therefore, we can say that;

• $P_{1} V_{1} = P_{2} V_{2}$

After substituting the given values of the pressure and the volume in the equation, we get:

• $748\times 22.5 = 725\times V_{2}$
• V₂ = $23.2L$

Hence, after compression, the volume of the gas, V₂, measured is $23.2L$.