if 22 april 1970 was a wednesday ,what will be the day on 31 may 1999? (pls show steps for the answer)
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Given :-
- 22 April , 1970 = wednesday .
To Find :-
- 31 May , 1999 = ?
Solution :-
→ 22 April to 31 May = 8(April) + 31(May) = 39 days = (39/7) = 4 odd day.
Now,
→ 1970 to 1999 = 29 years + 7 Leap years. = 36 = (36/7) = 1 odd day.
So,
→ 22 April, 1970 to 31 May, 1999 = 4 + 1 = 5 odd day.
Therefore,
→ wednesday + 5 = Monday (Ans.)
Hence, it was Monday on 31 May, 1999.
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