Question

if 2205 = 3^a × 5^b × 7^c​

Answer 1

Step-by-step explanation:

2205 when factorized

we have numbers

3*3*5*7*7

so have 3² x 5¹ x 7²

Therefore by the given info

3^a=3². so a=2

5^b=5¹. so b=1

7^c=7². so c=2

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Answer 2

take the factors of 2205 by prime factorization method

factors :- 3×3×5×7×7

NOW WE CAN SAY THAT

■ 3×3 = 3^a => 3^a=3^2 => a=2

■ 5=5^b => b=5

■ 7×7=7^c => 7^2 = 7^c => c=2

a=2; b=1; c=2