if 220V potential difference is applied across an electric bulb, a current of 0.45A flows in the bulb. What must be power of the bulb
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13
p=vI,=220×0.45=99watt ,id anewer of your quation
Anonymous:
is it right
Answered by
6
Power = V*I
V=220V and I =0.45A
Power=220*0.45 = 99W
NOTE: Here in this case we are considering that all electrical energy is converted to light energy. Otherwise answer can differ according to question given.
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