Math, asked by narendrakumar6417, 6 months ago

If 2²n-1=1/8n-3, then what is the value of n is

Answers

Answered by soupals1upv

0

(4n-1 )(8n-3) =1 => 32n² -8n-12n+3 -1= 0

=> 32n²-20n +2 =0 => 16n²-10n+1 =0

=> 16n²-2n-8n+1 =0 => 2n(8n-1)-1(8n-1)=0

=> (2n-1)(8n-1)=0 => n=½, n= ⅛

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