If 2²n-1=1/8n-3, then what is the value of n is
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(4n-1 )(8n-3) =1 => 32n² -8n-12n+3 -1= 0
=> 32n²-20n +2 =0 => 16n²-10n+1 =0
=> 16n²-2n-8n+1 =0 => 2n(8n-1)-1(8n-1)=0
=> (2n-1)(8n-1)=0 => n=½, n= ⅛
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