Math, asked by gunumohanty123456789, 4 months ago

If 22x - 3 = (64)*, find the value of x.​

Attachments:

Answers

Answered by SaakshiNB
8

Answer:

x = -3/4

Step-by-step explanation:

2^{(2x-3)}=(64)^x\\\\\\2^{(2x-3)} = (2^6)^x\\\\\\2^{(2x-3)} = 2^{6x}\\\\\\Equating~Powers\\\\\\2x-3=6x\\\\\\2x-6x=3\\\\\\-4x=3\\\\\\x=\frac{-3}{4}

Similar questions