Math, asked by sarah8744, 8 months ago

If 23 + 1 = 3, then the value of x is​

Answers

Answered by Anonymous
7

Answer:

If x=2+2*2/3+2*1/3 what is the value of x^3-6x^2+6x?

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Given that x = 2 + 2^(2/3) + 2^(1/3)

so x - 2 = 2^(2/3) + 2^(1/3)

=(x-2)^3 = [2^(2/3)+2^(1/3)]^3

use (a-b)^3= a^3 - b^3 - 3ab(a-b)

and (a+b)^3= a^3 + b^3 + 3ab(a+b) formulae.

or x^3 - 8 - 6x(x-2) = 2^2 + 2^1 + 3*[2^{(2/3)+(1/3)}[2^(2/3)+2^(1/3)

or x^3 - 8 - 6x^2 + 12x = 4 + 2 + 6(x-2)

or x^3 - 8 -6x^2 + 12x = 6 + 6x - 12

or x^3 - 6x^2 +6x = 2

Answered by VaishnaviTewari
0

Answer:

your question ( equation ) might be wrong check this question again

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