Question

If 2³ⁿ × 2² × 10 = 2560, find the value of n.​

Answer 1

(2^3n)*(2^2)*10=2560

(2^3n)*4=256

(2^3n)=64

(2^3n)=(2^6)

3n=6

n=2

Answer 2

Answer:

n=2

Step-by-step explanation:

2³ⁿ × 2² × 10 = 2560                  [∵a^m * a^n = a^(m+n)]

2³ⁿ⁺²=2560/10

2³ⁿ⁺²=256

2³ⁿ⁺²=2⁸

we know that if bases are equal then powers should be equal

                          3n+2=8

                          3n=8-2

                          3n=6

                          n=6/3

                       ∴ n=2