Math, asked by nyathakanisaideep, 4 months ago

If (23)x = 0. 23)y=1000, then find the value of 1/x-1/y​

Answers

Answered by fukkiraza
1

Answer:

23x=0.23

so therefore

x=0.01

then 1/0.01 -1/1000=99.999

Answered by chinnadarling162
0

Answer:

2/3 =(1/x-1/y)

Step-by-step explanation:

given 23x= 0.23y=1000

by applying log on both side

x log(23)=log1000

x log(23)=log 10^3. ( log 10=1)

log(23)=3/x. equation 1

log(0.23) =log(1000)

y log(23/100)=log10^3

log(23/100)=3/y. equation 2

equation 1 - equation 2

log(23)-log(23/100) = 3(1/x-1/y)

log((23/23/100))=3(1/x-1/y)

log(10^2)=3(1/x-1/y)

2/3=1/x-1/y

and solving we get

1/x-1/y = 2/3

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