Math, asked by rinkusingh050787, 2 months ago

If (2³x-¹ + 10) ➗ 7=6 ,find the value of x​

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Answered by radhikajhunjhunwala5
3

Answer:

2

Step-by-step explanation:

(2^3x-1 + 10) ÷ 7 = 6

2^3x-1 +10 = 7*6

2^3x-1 + 10 =42

2^3x-1 = 42–10

2^3x-1 = 32

2^3x-1 = 2^5

3x-1 = 5 ( as the bases are equal , powers are equal a^b = a^c , b = c laws of indices).

3x-1 =5

3x= 5+1

3x= 6

x= 6/3 = 2

Ans : 2

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