If (2³x-¹ + 10) ➗ 7=6 ,find the value of x
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Step-by-step explanation:
(2^3x-1 + 10) ÷ 7 = 6
2^3x-1 +10 = 7*6
2^3x-1 + 10 =42
2^3x-1 = 42–10
2^3x-1 = 32
2^3x-1 = 2^5
3x-1 = 5 ( as the bases are equal , powers are equal a^b = a^c , b = c laws of indices).
3x-1 =5
3x= 5+1
3x= 6
x= 6/3 = 2
Ans : 2
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