If (2³x-¹+10) /7 =6 , then the value of 'x' is
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(2^3x-1 +10)÷7=6
(2^3x-1 +10)/7=6
(2^3x-1 +10)=42
2^3x-1=42–10=32
(2)^3x-1=(2)^5
3x-1=5
3x=6
x=6/3
x=2
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