If 23x + 27y = 73 and 27x + 23y = 77. Then find x and y.
Answers
x = 2 and y = 1
Step-by-step explanation:
We have,
27x + 31y = 85
31x + 27y = 89
(1)
To find, the values of x and y=
By substitution method,
From (1),
27x + 31y 85
- 27x = 85 - 31y
85 - 31y
27
Put x = 85 – 31y
.
(A)
27 in (2), we get 85 31y
31(
27
+ 27y = 89
2635961 y + 729y 27 = 89
- 2635 232y = 89 x 27 = 2403
-232y = 24032635 = -232 - y = 1
Put y = 1 in (A), we get
85 – 31 54
27
27
- X = 2
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Answer:
x = 2 and y = 1
Step-by-step explanation:
We have,
27x + 31y = 85 ......(1)
31x + 27y = 89 ......(2)
To find, the values of x and y=
By substitution method,
From (1),
27x + 31y = 85
⇒ 27x = 85 - 31y
⇒ x=\dfrac{85-31y}{27}x=2785−31y ..... (A)
Put x=\dfrac{85-31y}{27}x=2785−31y in (2), we get
31(\dfrac{85-31y}{27})+27y=8931(2785−31y)+27y=89
⇒\dfrac{2635-961y+729y}{27}=89272635−961y+729y=89
⇒ 2635-232y=89\times 27=24032635−232y=89×27=2403
⇒-232y=2403-2635=-232−232y=2403−2635=−232
⇒ y = 1
Put y = 1 in (A), we get
x=\dfrac{85-31}{27}=\dfrac{54}{27}x=2785−31=2754
⇒ x = 2