if 23x3 is a multiple of 11 and x is a single digit what are possible values of x?
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hey!! First we have to recall the divisibility rule of 11. it indicates that the sum of the alternating digits should be 0 or 11.
Now, coming to the question
2+3+ ×+3= multiple of 11
(2+×)-(3+3)=0
(2+×)-6 = 0
2+×=6
×=6-2
×=4
Thus, the value of × is 4.
hope it helps u:-)
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Now, coming to the question
2+3+ ×+3= multiple of 11
(2+×)-(3+3)=0
(2+×)-6 = 0
2+×=6
×=6-2
×=4
Thus, the value of × is 4.
hope it helps u:-)
plzz mark it as branliest
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