if 23z13 is divisible by 9. Find the value of z.
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We know that the given number 67y19 is divisible by 9.
And, if a number is divisible by 9 then sum of digits must be a multiple of 9.
i.e., 6+7+y+1+9= multiple of 9
y+23=0,9,18,27…
Here y is a digit, where, y can have values between 0 and 9.
y+23=27 which gives y=4.
Hence, y=4.
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