if 24 .125=24+A/10+B/100+C/1000.find A+B+C
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abc.xyz number can be written as
a*100+b*10+c*1+x/10+y/100+z/1000
On this basis A=1,B=2,C=5
A+B+C=8
But the equation has many A,B,C s
a*100+b*10+c*1+x/10+y/100+z/1000
On this basis A=1,B=2,C=5
A+B+C=8
But the equation has many A,B,C s
lovepreetpaprapb572e:
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Answered by
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by taking lcm of rhs
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