Question

if 24.125=24+A/10+B/100+C/1000,then findA+B+C

Answer 1

24.125=24+A/10+B/100+C/1000
Subtact 24 from both sides:
0.125 = A/10+B/100+C/1000
0.125 = 1/10 + 2/100 + 5/1000
Therefore
1/10 + 2/100 + 5/1000 = A/10+B/100+C/1000

Comparing the numerators
A = 1
B = 2
C = 5

A + B + C = 1 + 2 + 5 = 8

Answer 2

Answer:

Step-by-step explanation:

24.125=24+A/10+B/100+C/1000

Subtact 24 from both sides:

0.125 = A/10+B/100+C/1000

0.125 = 1/10 + 2/100 + 5/1000

Therefore

1/10 + 2/100 + 5/1000 = A/10+B/100+C/1000

Comparing the numerators

A = 1

B = 2

C = 5

A + B + C = 1 + 2 + 5 = 8