If 24 labour can dig a trench in 18 days by per 7 hours working per day, how many labour required to digging just double pit in 16 days by 9 hours working per day ?
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Given :- If 24 labour can dig a trench in 18 days by per 7 hours working per day, how many labour required to digging just double pit in 16 days by 9 hours working per day ?
Solution :-
given that,
- M1 = 24 labour
- D1 = 18 days .
- W1 = 1 pit
- H1 = 7 hours .
- M2 = Let x labour .
- D2 = 16 days.
- H2 = 9 hours .
- W2 = 2 pit (double.)
we know that,
- (M1 * D1 * H1)/W1 = (M2 * D2 * H2)/W2
- work is inversely proportional .
so, putting values we get,
→ 24 * 18 * 7 * 2 = x * 16 * 9 * 1
→ 3 * 2 * 7 = x
→ x = 42 labours (Ans.)
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