If 24OO J of energy is used to heat up a 3 kg copper block from 20 C to 22 C. What are the specific heat capacity of copper and the heat capacity of the copper block?
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TOPIC :- HEAT TRANSFER
CONCEPT :- Heat transfer takes place from two bodies having some temperature difference which follows following formulas :-
FORMULA
∆Q = m S ∆T , where S = specific heat capacity
∆Q = C ∆T. , C = mS = heat capacity.
STEPS
Given,
m = 3 kg.
∆Q = 2400 J
∆T = 23-22 = 2 °C
Using ∆Q = m S ∆T
=> 2400 = 3 × S × 2
=> S = 400 J / Kg K
Now,
C = m S
= 3 × 400
= 1200 J /K
ADDITIONAL DETAILS FOR IIT-JEE
- The difference between specific heat capacity and heat capacity is that the former is independent of mass while later depends on mass.
- Latent heat of vaporisation Lvap = ∆Q/m
- Latent heat of fusion Lfus = ∆Q/m
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