Question

If 25 men can do a piece of work in 36 days working 10 hours a day, then how many men are required to complete the work working 6 hours a day in 20 days? ​

Answer 1

$\huge{\fbox{\fbox{\orange{\mathfrak{Answer\::}}}}}$

75 men

➡

$number \: of \: men \times \frac{1}{number \: of \: days \: \times \: time}$

➡️So, given 25 men × 36 days × 10hours

➡️If the number of men=x

&duration is 6 hrs/day and complete it in 20 days.

$25 \times 36 \times 10 = x \times 20 \times 6$

➡️cancel the digit by transposing to LHS.

$\huge{\fbox{\mathfrak{x = 75}}}$

So, the workers required to complete the work is 75 men

Answer 2

75 men are required to do the same work

Step-by-step explanation:

Given:

25 men can do a piece of work in 36 days by working 10 hours a day

To find:

number of men required to complete the same work in 6 hours a day in 20 days

Solution:

Let's say,

$M_{1}$ = men required initially = 25

$D_{1}$= days required intially = 36

$h_{1}$= hours required intially = 10

$D_{2}$= days required later = 20

$h_{2}$= hours required later= 6

$m_{2}$=?

As we know the work is same both the times

Using the ratio & proportion concept

Thus, $\frac{{m_{1}d_{1} h_{1} } }{w_{1} } =\frac{{m_{2}d_{2} h_{2} } }{w_{2} }$

∴ ${{(25)} (36) (10)} } }={{m_{2} (20) (6) } } }$

∴ $9000 = m_{2} (120)$

∴ $\frac{9000}{120} = m_{2}$

∴ $m_{2}=\frac{9000}{120}$

∴ $m_{2}=75$

m2 = 75

Thus, 75 men are required to complete the work by working 6 hours a day for 20 days.

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