Physics, asked by pragyan9721, 9 months ago

If 25 ml of acetone is present in 150 ml of its aqueous solution, calculate the concentration of solution.

Answers

Answered by kangarooboii
8

Answer:

14.8%

Explanation:

acetone = 25 ml

solution = 150 ml + 25 ml

percentage = (25 × 100)/ 175

                    = 14.8%

Answered by Anonymous
22

Answer:

14.28%

Given:

  • 25 ml of acetone is present in 150 ml of its aqueous solution

To Find:

  • Concentration of solution.

Solution:

Volume of solute = 25 ml

Volume of solvent = 150 ml

Volume of solution = (25 + 150)ml

=> 175ml

We know :-

\sf{} Concentration =\dfrac{Volume\ of\ solute}{Volume\ of\ solution}\times 100

Put their values and solve it.

\to \sf{}Concentration =\dfrac{25}{175}\times 100

\to \dfrac{1}{7}\times100

\sf{\to 14.28\%}

Therefore concentration of solution is equal to 14.28%

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