Question

If 25(n-1) +100 = 5(2n-1)
+100 = 5(2n-1), find the value of n.
(2n-1)​

Answer 1

Answer:

n=2

Step-by-step explanation:

I hope you mean,

25n−1+100=52n−125n−1+100=52n−1

⟹52n−2+100=52n−1⟹52n−2+100=52n−1

⟹52n−15+100=52n−1⟹52n−15+100=52n−1

Let, 52n−1=t52n−1=t

∴t5+100=t∴t5+100=t

⟹4t5=100⟹4t5=100

⟹t=125⟹t=125

So, we get —

52n−1=5352n−1=53

⟹2n−1=3⟹2n−1=3

⟹2n=4⟹2n=4

⟹n=2⟹n=2

∴n=2∴n=2

Thank you!

Answer 2

Answer:

answer is

Step-by-step explanation:

given relation

25(n-1)+100=5(2n-1)+100

5*5(n-1)=5(2n-1)

5(5n-5)=5(2n-1)

5n-5=2n-1

3n=4

n=4/3

for the valye of 2n-1

2n-1=2*4/3-1

=8/3-1

=5/3