Question

If (25)n×(31)n=(1015)n then the value of (13)n×(52)n is n>0

Answer 1

Answer:

Answer:25n×31n=1015n

25n×31n=1015n=> 775n²=1015n

25n×31n=1015n=> 775n²=1015n=> (Cancelling n from both sides as we don't need any negative value here)

> 775n=1015

Answer:25n×31n=1015n=>

n= 1015/775

1015/775=> n = 1.309(approx)

Answer:25n×31n=1015n=> 775n²=1015n=> (Cancelling n from both sides as we don't need any negative value here)=> 775n=1015=> n= 1015/775=> n = 1.309(approx)Then finding the value of 13n× 52n Condition is n>0

Answer:25n×31n=1015n=> 775n²=1015n=> (Cancelling n from both sides as we don't need any negative value here)=> 775n=1015=> n= 1015/775=> n = 1.309(approx)Then finding the value of 13n× 52n Condition is n>0 13×1.309 × 52× 1.309

• Answer:25n×31n=1015n=> 775n²=1015n=> (Cancelling n from both sides as we don't need any negative value here)=> 775n=1015=> n= 1015/775=> n = 1.309(approx)Then finding the value of 13n× 52n Condition is n>0 13×1.309 × 52× 1.309=> 1158.31(approx)(ans)

Answer:25n×31n=1015n=> 775n²=1015n=> (Cancelling n from both sides as we don't need any negative value here)=> 775n=1015=> n= 1015/775=> n = 1.309(approx)Then finding the value of 13n× 52n Condition is n>0 13×1.309 × 52× 1.309=> 1158.31(approx)(ans)