If 25^x-1 = 5^2x-1 - 100, then find x
Answers
Answered by
9
hi friend,
=================================
25^x-1 = 5^2x-1 - 100
→5^2x-2=5^2x-1 - 100
→ 5^2x/5²=5^2x/5-100
→5^2x/25=5^2x-500/5
multiplying 5 on both sides,
→5^2x/5=5^2x-500
→ 5^2x=5^2x+1-2500
→5^2x+1-5^2x=2500
→5^2x(5-1)=2500
→5^2x=2500/4
→5^2x=625
→5^2x=5⁴
as bases are equal
2x=4
x=2
=============================
I hope this will help u :)
=================================
25^x-1 = 5^2x-1 - 100
→5^2x-2=5^2x-1 - 100
→ 5^2x/5²=5^2x/5-100
→5^2x/25=5^2x-500/5
multiplying 5 on both sides,
→5^2x/5=5^2x-500
→ 5^2x=5^2x+1-2500
→5^2x+1-5^2x=2500
→5^2x(5-1)=2500
→5^2x=2500/4
→5^2x=625
→5^2x=5⁴
as bases are equal
2x=4
x=2
=============================
I hope this will help u :)
Answered by
0
Answer:
wadwadwd
Step-by-step explanation:
answer is 4
adwsawsd,asdlsld,a
Similar questions