if 25^x-1 = 52^2x-1-100
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Assuming the question as: 25x – 1 = 52x – 1 – 100 ⇒ (52)x – 1 = 52x – 1 – 100 ⇒ 52x – 2 = 52x – 1 – 100 ⇒100 = 52x – 1 – 52x – 2 ⇒ 52x – 1 – (52x – 1)/5 =100 → (1) Let 52x – 1 = a Equation (1) becomes, a – a/5 =100 ⇒ 4a/5 =100 ⇒ a = (100 × 5)/4 = 125 Therefore, 52x – 1 = 125 ⇒ 52x – 1 = 53 ⇒ 2x – 1 = 3 ⇒ 2x = 4 ∴ x = 2
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