If 25(x-1 is the power of 25) = 52^x-1(where x-1 is the power of 52) -100 , find the value of x.
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hey user,
if 25^x-1= 52^x-1-100
25^x-1 =52^x-1-10^2
we know that if there is subtraction in the normal condition, it becomes division in the powers
therefore,
x-1= x-1÷2
taking 2 on the other side,
2x-2= x-1
x=1
sudhirdubeyin:
sorry to say but it is wrong
putting the value of X=1 I can't get LHS=RHS
okay thanks for the feedback
I'll try to correct my mistake
I think the question is wrong
tried to solve it in all ways
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