If 250 ml of 1M nacl is to be prepared, how many grams of nacl is required???...... plz ans fast
Answers
Answered by
4
Here,
1M = no. of moles / volume In liter
Given volume = 250 ml = 0.25 L
no. of moles = 1×v = 0.25 moles
molecular Mass of nacl = 58.5 × 0.25 = 14.6 g
thus 14.6 g nacl is needed
1M = no. of moles / volume In liter
Given volume = 250 ml = 0.25 L
no. of moles = 1×v = 0.25 moles
molecular Mass of nacl = 58.5 × 0.25 = 14.6 g
thus 14.6 g nacl is needed
Answered by
3
1M nacl means
1000ml solution contains 1 mole of nacl
So,
250 ml contains 0•25 moles of nacl, i. e, 0.25× 58•4g=14•6gm of Nacl
1000ml solution contains 1 mole of nacl
So,
250 ml contains 0•25 moles of nacl, i. e, 0.25× 58•4g=14•6gm of Nacl
rohitFairytail:
Why
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