IF 250 volt P.D. is applied a cross an electric bulb, a current of O. 5 A flow in the bulb. the power of the bulb must be________
Answers
Answered by
1
Answer:
Power is defined as Voltage × Current
Therefore power of the bulb will be 250×0.5=125watt
Answered by
1
Explanation:
P=VI
P= 250× 0.5
P= 125 watt
if you get it then plz mark it as brainliest ans....
Similar questions