Question

If 25m = 0.0125 the m is equal to​

Answer 1

Answer: So, you know the molarity and volume of the target solution, which means that you can determine how many moles of hydrochloric acid it must contain

c

=

n

V

⇒

n

=

c

⋅

V

n

H

C

l

=

0.040 mol

L

−

1

⋅

1.00

L

=

0.040 moles HCl

Now your task is to determine what volume of the concentrated solution would contain this many moles of hydrochloric acid.

c

=

n

V

⇒

V

=

n

c

Plug in your values to get

V

=

0.040

moles

0.25

mol

L

−

1

=

0.16 L

Expressed in milliliters and rounded to two sig figs, the answer will be

V

=

160 mL

This is exactly what the formula for dilution calculations allows you to do

moles of solute in concentrated solution



c

1

×

V

1

=

moles of solute in diluted solution



c

2

×

V

2

Here you have

c

1

,  

V

1

- the molarity and volume of the concentrated solution

c

2

,  

V

2

- the molarity and volume of the diluted solution

Once again you will have

V

1

=

c

2

c

1

⋅

V

2

V

1

=

0.040

M

0.025

M

⋅

1.00 L

=

160 mL

So, you would prepare this solution by adding enough water to your  

160-mL

sample of  

0.25-M

hydrochloric acid solution to make the total volume of the resulting solution equal to  

1.00 L

check the attachment please

Step-by-step explanation: