Question

If 25sinx-2(5sinx) - 3=0, x= [0,2r], then smallest value of x lies in -​

Answer 1

Answer:

Answer

Correct option is

D

4

(sinx+3)(2sinx−1)=0

∴sinx=

2

1

as sinx



=−3

∴x−

6

π

,π−

6

π

=

6

5π

i.e., two values in 0 to π.

No value in π to 2π as sinθ will be −ive and two values again in 2π to 3π. Thus there will be only four values of x