Question

if 27^2x-1=(243)^3 find value of 5^2x-4

please solve with method ​

Answer 1

Step-by-step explanation:

(3)3(2x-1)=(3)5(3)

(3)6x-3=(3)15

Or, 6x-3=15

or,6x=18

or,x= 3

now, (5)2x-4

or,(5)2×3-4

or,(5)6-4

or,(5)2

= 25 (answer......)

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Answer 2

Answer:

${27}^{2x - 1} = ( {243})^{3} \\ { {3}^{3} }^{2x - 1} = { {3}^{5} }^{3} \\ {3}^{6x - 3} = {3}^{15} \\ compairing \: power \\ 6x - 3 = 15 \\ 6x = 18 \\ x = 3 \\ {5}^{2x - 4} \\ {5}^{2 \times 3 - 4} \\ {5}^{6 - 4} \\ {5}^{2} \\ 25$