Question

if (27)^2x-1=(243)^3 then find the value of x

Answer 1

(27)^2x-1 = 243^3

(3^3)^2x-1 = (3^5)^3

Since, (a^m)^n = a^mn

3^(6x-3) = 3^15

By equating,

6x-3 = 15

6x=18

x=3

Answer 2

Hey✨✨✨✨✨

Here is your answer,⬇⬇⬇⬇

27 can be written as 3^3 and 243 can be written as 3^5

(3^3 ) ^2x-1 = (3^5)^3

Multiplying the powers,

3^6x-3 = 3^15

The powers are equal when the base numbers are same

So,

6x-3 = 15

6x = 15+3

6x = 18

X = 3

Hope it helps you!✔✔✔✔