Question

If 27 +3j – 6k, 67 – 2; +3k are two
consecutive sides of a triangle, then perimeter of
triangle is​

Answer 1

Step-by-step explanation:

2i+3j−6k∣=

4+9+36

=

49

=7

∣6i−2j3k∣=

36+4+9

=

49

=7

∣3i−6j−2k∣=

9+36+4

=

49

=7

perimeter =7+7+7=21