If 27 +3j – 6k, 67 – 2; +3k are two
consecutive sides of a triangle, then perimeter of
triangle is
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Step-by-step explanation:
2i+3j−6k∣=
4+9+36
=
49
=7
∣6i−2j3k∣=
36+4+9
=
49
=7
∣3i−6j−2k∣=
9+36+4
=
49
=7
perimeter =7+7+7=21
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