Question

If 27.5 moles of water was produced, how many grams of methanol were
combusted?​

Answer 1

Answer:

Multiply the resulting number by the number of grams per mole of product to find the mass of product able to be produced by the given amount of reactant. There are 2.1749 moles of NaCl and one mole equals 58.243 grams. 2.1749 × 58.243 = 126.67, so the 50.000 g of Na used in the reaction can create 126.67 g of NaCl.21.