Question

If 270 watts of power is used in 42 seconds, how much work was done?

Answer 1

Given

• Power = 270 Watts
• Time = 42 seconds

To Find

• Work done

Solution

We know that

$\rm \longrightarrow W=Pt$

Here

• W = Work done
• P = Power
• t = Time

Units

• W = Joule (J)
• P = Watt (W)
• t = second (s)

According to the question

We are asked to find the work done

Therefore

We must find "W"

Given that

• Power = 270 Watts
• Time = 42 seconds

Hence

• P = 270 W
• t = 42 s

Substituting the values

We get

$\rm \longrightarrow W=270 \times 42 \ J$

Therefore

$\rm \longrightarrow W=11340 \ J$

Hence

Work done = 11340 J

Answer 2

Required answer -

Question -

${\bullet}$ If 270 watts of power is used in 42 seconds, how much work was done?

Given that -

${\bullet}$ Power = 270 watts.

${\bullet}$ Time = 42 seconds

To find -

${\bullet}$ Work done

Solution -

${\bullet}$ Work done = 11340 J

Using concept -

${\bullet}$ Formula to find work done.

Using formula -

${\bullet}$ W = Pt

~ Where,

◍ W denotes work done (Joules)

◍ P denotes power (Watts)

◍ t denotes time (Seconds)

~ Here,

◍ W = ? [To find]

◍ P = 270 watts

◍ t = 42 seconds

~ Let's put the values,

➝ W = Pt

➝ W = (270)(42)

➝ W = 270 × 42

➝ W = 11340 J

• Henceforth, work done is 11340 Joules (J).