If 2791A is divisible by 9 supply the missing digit in place of A
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Answered by
37
divisibility by 9 is when some of digits is a multiple of 9
2+7+9+1+A=kx9 where k is some constant
19+A=27 as A should be less than 10
A =8
2+7+9+1+A=kx9 where k is some constant
19+A=27 as A should be less than 10
A =8
Answered by
36
For a number to be divisible by 9 its sum of digits must be divisble by 9
so
2 + 7 + 9 + 1 + A = 19+A
put A = 8
we get sum as 27 which is divisible by 9
So A = 8
27918 is divisible by 9
so
2 + 7 + 9 + 1 + A = 19+A
put A = 8
we get sum as 27 which is divisible by 9
So A = 8
27918 is divisible by 9
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