If 28 cows cost as much as 10 horses,
then how many horses can be
exchanged for 126 cows ?
Answers
Answered by
0
Answer:
Let x rupees and y rupees be the cost of one horse and one cow respectively.
Therefore, according to the question,
3x+5y=20500 ...(i)
2x+3y=13400 ...(ii)
On multiplying (i) by 2 and (ii) by 3 and subtracting, we get
6x+10y=41000
−
6
x
−
+
9y=
−
4
0200
y=800
On putting y=800 in (i), we get
3x+4000=20500⇒x=5500
∴cost of one horse=Rs. 5500 and
cost of one cow=Rs.800
Now, the cost of 5 horses and 4 cows=5×5500+4×800=Rs.30700
Answered by
1
Answer:
1260 horses answer is if right give a heart
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