If 28 grams of iron (Fe) reacts, how many moles of iron (III) chloride (FeCl(3)) would be produced?
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The first step in almost any chemistry question involving a reaction is to balance the equation:
3Cl2 + 2Fe --> 2FeCl3
From how the equation is phrased, this must mean that we assume Fe is in excess.
Use the balanced equation to set up a proportion of the amount of moles of Iron (III) chloride to every Cl2 molecule. Using the proportion given in the equation, and setting it equal to the given amount of iron (III) chloride and the unknown amount of chlorine gas will help you find your answer.
2 FeCl3/3 Cl2 = 0.422 mol FeCl3/ x mol Cl2
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