if 28 of N2 completely reacts with 4 gram of H2 amount of Nh3 formed will be N2+3H2----------->2NH3 (a)22.66g (b) 32g (c) 34g (t) 30g
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I think the answer will be 30g
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Answer: (a) 22.66 g
Explanation:
N2 + 3H2 ---------------------> 2NH3
1 mole 3 mole 2 mole
3 mole H2 produces 2 mole NH3.
Molecular mass of (H2, NH3) = (2, 14 + 3) = (2, 17)
Therefore, (3 x 2) g H2 produces (2 x 17) g NH3
or, 1 g H2 produces 34/6 g NH3
or, 4 g H2 produces 4 x (34/6) g NH3 = 22.66 g NH3
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