Math, asked by TejaswiniTupe, 6 months ago

if 28 workers can compete work in 4 days then in how much day 14 workers will compete there work​

Answers

Answered by sidd5449
0

Answer:

8 days

Step-by-step explanation:

Answered by sckbty72
1

Answer:

8 days

Step-by-step explanation:

Let the total work be unity.

Let work done by 1 worker in 1 day be x

So, Work done by 28 workers in 4 days = 28*4*x = 112x

112x = 1 (total work done)

So, x = 1/112

Work done by 14 workers in 1 day = 14x = 14/112 = 1/8

Total work = 1

So, no. of days required = Total work / Work done by 14 workers in 1 day

                                         = 1/ (1/8)

                                         = 8 days

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