Question

If 280 J of work is done in carrying a charge of 2 C from a place where the potential is -12 V to another place where potential is V, calculate the value of V

Answer 1

Answer:-

V = 128v

Given :-

Work done to carry the charge = 280j

Amount of charge = 2C

To find :-

The value of V at potential second.

Solution:-

Let the first potential be $V_1$ and second potential be $V_2$

→$V_1 = -12v$

Then ,

→$V = V_2 - V_1$

Now ,

To calculate the potential difference we use the following formula:-

$\huge V = \dfrac{W}{Q}$

→$V_2 - V_1 = \dfrac{W}{Q}$

Put the given value ,

→$V_2 - (-12) = \dfrac{280}{2}$

→$V_2 +12 = 140$

→$V_2 = 140 -12$

→$V_2 = 128v$

hence,

The value of V is 128v .